h2+o2=h2o balanced equation

Ok so I have 100g of Hydrogen and 100g of Oxygen in. How do you think about the answers? here's the steps for these types of problems.. 6) in some cases, you're asked to determine yield. In a periodic table it is called the atomic weight. this will not satisfy the Oxygen's thought as you have 3 on left and 2 on right. The atoms on the left have to be exactly equal to those on the right. Get your answers by asking now. What to do? There is only 1 Oxygen on the right side, so multiply a few items by 2 and: What the equation literally states is 2 moles of Hydrogen molecules react with 1 mole of Oxygen molecules to produce 2 moles of water molecules. What it needs is to have equal numbers of atoms on each side of the "->" sign. First i notice that there is one Oxygen on the right and 2 oxygen atom on the left, then i decided to balance the O. Likewise, a mole of Hydrogen molecules weighs 2 grams. A certain lead ore contains the compound PbCO3. used 6.250 moles means 50-6.25 = 43.75 moles remains, 43.75 moles H2 x (2 g H2 / 1 mole H2) = 87.5 g H2 remains. Ordinarily 1 mole of Oxygen atoms weighs 16 grams. The chief was seen coughing and not wearing a mask. You now get . Complete the following reaction CH3 minus ch double bond ch2 + H2O Khate Kalam 1000 Madhya wali To make sure the O levels are the same, we change the number of H2O. and i'd be like 'oh no, the right only has 1 O!'. which makes you more jittery coffee or tea? 3. so now you have H2+02 =2H20. Hence, 6.25 moles of water molecules will be produced. A certain lead ore contains the compound PbCO3. Answer: B. To find how much remains of the other one, use the oxygen to find how much you used, then subtract that value to find how much remains: 100g O2 ( 1mol O2 / 32g O2)(2 mol H2 / 1 mol O2) (2 g H2 / 1 mol H2) = 12.5g H2 used. This equation is not balanced. After doing this all of the atoms for their respective elements will be balanced. A mole is just a number like PI, but chemists never actually use the number itself. which makes you more jittery coffee or tea? You can sign in to vote the answer. Finding the weight of water is just a matter of multiplying the number of moles by the molecular weight. If two moles of hydrogen atoms combined with 1 mole of Oxygen atoms, the mole of H2O produced would weigh 18 grams: However, the equation in the problem states: This equation is not balanced. since you have 50 moles, you have excess H2 and that makes O2 the limiting reagent.... 3.125 moles O2 x (2 moles H20 / 1 mole O2) = 6.250 moles H20, 6.250 moles H20 x (18.0 g H20 / 1 mole H20) = 112.5 g. now let's see what else you need to know.... you started with 50.0 moles. I went to a Thanksgiving dinner with over 100 guests. Get your answers by asking now. Chem help, chemical bonds and wavelength. you have 3.125 moles O2. Which of the following can be characterized as a strong electrolyte? You have 2 Hs on both sides, but 2 O as a reactant and only 1 O in the products. 3. so now you have H2+02 =2H20. Which of the following can be characterized as a strong electrolyte? Thanks! There is a trick involved as well. from balanced equation 2 H2 reactions with 1 O2. New questions in Chemistry. Join Yahoo Answers and get 100 points today. A sample of the ore weighing 4.301 g was treated with nitric acid, which dissolved the PbCO3. Email if you have questions. 4. it's easy! How much H2O results is found by examining the balanced equation. A. H2 + O2 - > H2O B. H2 + O2 - > 2H2O C. 2H2 + O2 - > 2H2O D. 2H2 + 2O2 - > 2H2O There is a 1 to 1 ratio between the moles of Hydrogen molecules and water molecules. FInd the limiting reageant by finding the moles of eachand dividing by the constant, and setting up a correct equation: 100g H2 (1 mol H2 / 2g H2) = 50 mol H2 / 2 = 25, 100g O2 (1 mol O2 / 32g O2) = 3.125 mol O2, The oxygen will run out first, therefore it is limiting. What we basically need to do is make sure we have the same number of atoms on each side. Question: The equation for water is H2 +O2 → H2O. Knowing the molecular weights, now calculate the number of moles of each gas present. Because there was less Oxygen than Hydrogen, the Oxygen could be said to be the "limiting reagent.". 1 mole of Hydrogen atoms weighs 1 gram. This equation is 2 H2O (liquid) = 2 H2 (gas) + O2 (gas)There must be 4 atoms / 2 diatomic molecules of hydrogen on each side to yield O2This is the electrolysis of water.

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